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A 12 inch-wide conveyor unloads 5000 bushels of wheat per hour. At this speed, how many bushels per hour will an 18-inch-wide conveyor unload?

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12-inch wide conveyor unloads 5000 bushels of wheat per hour. At this same speed, the number of bushels that will be unloaded per hour by an 18-inch wide conveyor can be calculated below


\begin{gathered} 12\text{ = 5000} \\ 18=\text{?} \\ u\text{nload amount=}(5000*18)/(12)=(90000)/(12)=7500\text{ bushels per hour } \end{gathered}

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