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A 3.0kg cat and a 14kg dog exert a force of gravity on each other equal to 1.12 x 10^-10 N. how far apart are they

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The expression for the gravitational force between two bodies is given by:


F=G(m_1m_2)/(r^2)

where,

G: Cavendish's constant = 6.67*10-11Nm^2/kg^2

m1 = 3.0kg

m2 = 14kg

Solve the equation above for r:


\begin{gathered} r=\sqrt{(Gm_1m_2)/(F)} \\ r=\sqrt[]{\frac{(6.67\cdot10^(-11)\frac{Nm^2}{\operatorname{kg}^2})(3.0kg)(14kg)}{10\cdot10^(-10)N}} \\ r\approx1.67m \end{gathered}

Hence, the distance between the dog and the car is approximately 1.67m

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