Question

HELP! I need this ASAP!!A recursive rule for a sequence is given. Find the first four terms of the sequence. f(1) =5 f(n)= f(n-1) +3, where n is an integer and n ≥ 2

Answer 1

f(n) = f(n-1) + 3

substitute n= 2 in the above

f(2) = f (2-1) + 3

= f(1) + 3

= 5 + 3

= 8

substitute n = 3 in the formula

f(3) = f(3-1) + 3

= f(2) + 3

= 8 + 3

= 11

substituite n = 4

f(4) = f(4-1) + 3

= f(3) + 3

= 11 + 3

= 14

The first four terms are 5, 8, 11 and 14