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Amanda's Coffee Shop makes a blend that is a mixture of two types of coffee. A coffee costs Amanda $5.60 per pound, and type B coffee costs $4.55 per pound. This month, Amanda made 141 pounds of the blend, for a total cost of $728.70. How many pounds of type B coffee did she use?

User Lorenzog
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We are given that Amanda made 141 pounds of coffee. If "x" is the pounds of type A coffee and "y" is the amount of type b coffee then we can write this mathematically as:


x+y=141,(1)

We are also given that the cost of type A is $5.6 per pound and that the cost of type B is $4.55 per pound and that the total cost is $728.70, this can be written mathematically as:


5.6x+4.55y=728.7,(2)

Now, we solve for "x", first by subtracting "y" from both sides:


y=141-x

Now, we substitute the value of "y" in equation (2):


5.6x+4.55(141-x)=728.7

Now, we apply the distributive property in the parenthesis:


5.6x+641.55-4.55x=728.7

Now, we add like terms:


1.05x+641.55=728.7

Now, we subtract 641.55 from both sides:


\begin{gathered} 1.05x=728.7-641.55 \\ 1.05x=87.15 \end{gathered}

Now, we divide both sides by 1.05:


x=(87.15)/(1.05)

solving the operations:


x=83

Now, we substitute the value of "x" in equation (1):


\begin{gathered} y=141-83 \\ y=58 \end{gathered}

Therefore, the amount of coffee type A is 83 pounds and type B is 58 pounds.

User Kamo
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