1 Answer

Leifdenby · Answer 1 · 2023-09-08T21:29:37+0000

Given:

$6^{9\text{ }}\ast6^x=6^2$

To find the value of x, first apply exponential property which is:

$a^m\text{ }\ast a^{n\text{ }}=a^(m+n)$

Now we have:

$6^{9+x\text{ }}=6^2$

Since both bases are equal, let's remove both bases, take the exponent and find x:

$9\text{ + x = 2}$

Now subtract from both sides:

$9\text{ - 9 + x = 2 - }9$
$0\text{ + x }=\text{ -7}$
$x\text{ = -7}$

The value of x is -7

Please log in or register to add a comment.