185k views
2 votes
X^2 +2= 0I need help with solving this quadratic equation.

1 Answer

4 votes
Answer:
x\text{ = }-i\sqrt[]{2}\text{ or i}\sqrt[]{2}Step-by-step explanation:

The given quadratic equation is:


x^2+2=0

Subtract 2 from both sides


\begin{gathered} x^2+2-2=0-2 \\ x^2=\text{ -2} \end{gathered}

Find the square root of both sides


\begin{gathered} \sqrt[]{x^2}=\text{ }\sqrt[]{-2} \\ x=\sqrt[]{-2} \\ x=\pm\sqrt[]{2}*\sqrt[]{-1} \\ x\text{ =}\pm\text{ }\sqrt[]{2}i \\ x\text{ = }\pm i\sqrt[]{2} \end{gathered}
\begin{gathered} x\text{ = }-i\sqrt[]{2}\text{ or i}\sqrt[]{2} \\ \end{gathered}

User Vonetta
by
6.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.