Question

Sodium reacts with oxygen to produce sodium oxide.4Na(s)+O2(g)→2Na2O(s)If you have 16.0 g of Na , how many grams of O2 are required for the reaction?

Answer 1

5.57 grams

Explanations:

Given the reaction between sodium and oxygen expressed as:

`4Na(s)+O_2(g)\rightarrow2Na_2O(s)`

Given the following parameters

Mass of sodium = 16.0g

Determine the moles of sodium

`\begin{gathered} moles\text{ of Na}=\frac{mass}{molar\text{ mass}} \\ moles\text{ of Na}=(16)/(23) \\ moles\text{ of Na}=0.6957moles \end{gathered}`

According to stoichiometry, 4 moles of sodium reacts with 1 mole of oxygen, the moles of oxygen that reacted is given as;

`\begin{gathered} moles\text{ of O}_2=(0.6957)/(4) \\ moles\text{ of O}_2=0.1739moles \end{gathered}`

Determine the mass of oxygen that reacted

`\begin{gathered} mass\text{ of O}_2=mole* molar\text{ mass} \\ mass\text{ of O}_2=0.1739*32 \\ mass\text{ of O}_2=5.57grams \end{gathered}`

Hence the mass of oxygen that reacted is 5.57 grams