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6) 3x2 + 10X - 8We have to find the vertex

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Given:


3x^2+10x-8

To find the vertex, use the vertex formula below:


y\text{ = }a(x-h)^2+k

Where the vertex is: (h, k)

Thus, we have:


y=3x^2+10x-8


\begin{gathered} y+8=3x^2+10-8+8 \\ \\ y+8=3x^2+10 \end{gathered}

Factorize:


undefined

User GeorgDangl
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