Given data
*The given power is P = 2000 MW = 2000 × 10^6 W
*The given distribution voltage is V = 22 kV = 22 × 10^3 V
The formula for the current needed to carry the 2000 MW generated at a large power station is given as
![I=(P)/(V)](https://img.qammunity.org/2023/formulas/physics/college/qf3bvsiolzbmp97z8my992uawjvv6qt4a5.png)
Substitute the known values in the above expression as
![\begin{gathered} I=(2000*10^6)/(22*10^3) \\ =90.90*10^3\text{ A} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/c6vngoal3143fc58dsq4x4uctanclipam9.png)
Hence, the current needed to carry the 2000 MW generated at a large power station is I = 90.90 × 10^3 A