Recall that the area between the graphs of two functions on the interval [a,b] is:

Therefore, the area between f(x)=4√x and the x-axis with equation y=0, on the interval [4,9] is:
![\int ^9_4|4\sqrt[]{x}-0|dx=\int ^9_4|4\sqrt[]{x}|dx\text{.}](https://img.qammunity.org/2023/formulas/mathematics/college/mv0twsc1h4l6adn7bd658337ortfq822kk.png)
Notice that
![4\sqrt[]{x}>0,](https://img.qammunity.org/2023/formulas/mathematics/college/w3cp58bnrt7erimt7dut7mi18ho57or7si.png)
for all x in the given interval, therefore:
![\int ^9_4|4\sqrt[]{x}|dx=\int ^9_44\sqrt[]{x}dx=4\int ^9_4x^{(1)/(2)}dx=4(\frac{2x^{(3)/(2)}}{3})|^9_4=(8)/(3)(9^{(3)/(2)}-4^{(3)/(2)})=(8)/(3)(19)=(152)/(3).](https://img.qammunity.org/2023/formulas/mathematics/college/tmcbpymjk8xuwgxbgl535gczxc52zmzqfp.png)
Answer: 152/3.