Question

Find the value of the expression. 07-2 . (131 alw The value is I I

Answer 1

`\begin{gathered} \lbrack((3)/(5))^0\rbrack^(-2) \\ ((3)/(5))^0=0.6^0=1 \\ \Rightarrow1^(-2)=(1)/(1^2)=(1)/(1)=1 \\ \Rightarrow\lbrack((3)/(5))^0\rbrack^(-2)=1 \end{gathered}`