Given: A quadratic equation-

Required: To solve the equation by completing the square method.
Explanation: The general form of a quadratic equation is-

The given equation can be solved by the method of completing the square by adding and subtracting the term-

Hence, the given equation can be written as-

Now solving further as-

Thus,

This gives-

Final Answer: The solution to the equation is x=11 or x=1.