Question

Trig The last sub-problem of this section stumped me pls help

Answer 1

For this problem, we are given a triangle and we need to determine its height.

The distance of the UFO from point A is equal to the side c of the triangle, this side forms a right triangle with the height, where the height is the opposite cathetus from angle alpha and side c is the hypothenuse. We can use the sine relationship to determine the height, as shown below:

`\begin{gathered} \sin(87.4)=(h)/(425.58)\\ \\ h=425.58\cdot\sin(87.4)\\ \\ h=425.58\cdot0.9989706=425.14 \end{gathered}`

The height is approximately 425.14 km.