Question

Read each scenario below. Then select the answer that best completes each sentence.The power from a car engine is more than the power of a bicycle because a car engine does the same amount of work in time.Raul and Katrina equally shared a frozen lunch but heated each portion in two different microwaves. Katrina’s lunch was warm in one minute while Raul’s lunch took two minutes. The power used by Raul’s microwave must be the power used by Katrina’s because his microwave took time to do the same amount of work.

Answer 1

1. more than

2. less

3. less than

4. more

Step-by-step explanation:

Answer 2

a)The power from a car engine is more than the power of a bicycle because a car engine does the same amount of work in less time.

b)Raul and Katrina equally shared a frozen lunch but heated each portion in two different microwaves. Katrina’s lunch was warm in one minute while Raul’s lunch took two minutes. The power used by Raul’s microwave must be the less than the power used by Katrina’s because his microwave took more time to do the same amount of work.

Explanation

work:work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement

so

Step 1

a)The power from a car engine is more than the power of a bicycle because a car engine does the same amount of work in less time.

power is given by:

`P=\frac{\text{work done}}{time\text{ taken}}`

so, we can see the time is in the denominator, so as the car engine does the same work in less time, the power of the engine is more than the power of a bicycle

Step 2

Raul and Katrina equally shared a frozen lunch but heated each portion in two different microwaves. Katrina’s lunch was warm in one minute while Raul’s lunch took two minutes. The power used by Raul’s microwave must be the less than the power used by Katrina’s because his microwave took more time to do the same amount of work.

again, as the time is in the numerator

to more times, less power , so

`\begin{gathered} P_(katr\in a)=\frac{W_(katr\in a)}{\text{time taken}} \\ as\text{ the shares ase equal , the work neccesary to warm it is the same, so} \\ W_(katr\in a)=W_(raul) \\ so \\ P_(katr\in a)=\frac{W_(katr\in a)}{\text{time taken}}=(W_(katr\in a))/(1) \\ Praul=\frac{W_(katr\in a)}{\text{time taken}}=\frac{W_(katr\in a)}{\text{2}} \\ P_(raul)=\frac{W_(katr\in a)}{\text{2}}=(P_(katr\in a))/(2) \\ P_(raul)=(P_(katr\in a))/(2) \end{gathered}`

therefore,

the answer is

Raul and Katrina equally shared a frozen lunch but heated each portion in two different microwaves. Katrina’s lunch was warm in one minute while Raul’s lunch took two minutes. The power used by Raul’s microwave must be the less than the power used by Katrina’s because his microwave took more time to do the same amount of work.

I hope this helps you