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Identify the factors of the expression x^3 +4x^2-16x-64.

User Antonky
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Solution:

Consider the following polynomial:


x^3+4x^2-16x-64

By grouping terms, we get that the above polynomial is equivalent to the following expression:


(x^3+4x^2)+(-16x-64)

Now, we can apply common factor:


x^2(x^{}+4^{})-16(x+4)

again, applying a common factor, we get:


(x^2-16)(x+4)

Note that the left factor is a difference of squares, therefore, the above expression is equivalent to:


(x-4)(x+4)(x+4)

this is equivalent to:


(x-4)(x+4)^2

So that, we can conclude that the factors of the given expression are:


(x-4)

and


(x+4)^{2^{}}

and we can conclude that:


x^3+4x^2-16x-64=(x-4)(x+4)^2

User Timothy Kanski
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