2 Answers

Bardi Harborow · Answer 1 · 2023-05-15T12:02:41+0000

Solution

For this case we have the following number given:

$-3+\sqrt[]{3}i$

We can see that x = -3 and y = - sqrt(3)

The angle is given by:

$\arctan (\frac{-\sqrt[]{3}}{3})=-30=-(\pi)/(6)$

The radius would be:

$r=\sqrt[]{(3)^2+(-\sqrt[]{3})^2}=\sqrt[]{12}$

And the polar form would be given by:

$z=\sqrt[]{12}(\cos (-(\pi)/(6))+i\sin (-(\pi)/(6)))\text{ }$

Please log in or register to add a comment.