Question

Help with Algebra 2 question.14) An angle is in standard position and is terminal side pauses through point (-2,5), find sec.

Answer 1

Given:

An angle is in standard position and is terminal side passes through the point (-2,5),

Required:

To find the value of the secant function.

Step-by-step explanation:

The value of the secant function is given as:

`sec\theta=(r)/(x)`

Where

`r=√(x^2+y^2)`

Consider x= -2 and y = 5

Now calculate the value of r by using the formula:

`\begin{gathered} r=√((-2)^2+(5)^2) \\ r=√(4+25) \\ r=√(29) \end{gathered}`

Thus the required value is:

`sec\theta=(√(29))/(-2)`

Final Answer:

`sec\theta=-(√(29))/(2)`