![f(x)=(2(x+7)(x-3)^2(x+1))/(3(x-4)^3(x+5)(x+1))](https://img.qammunity.org/2023/formulas/mathematics/college/is205dupn0gy0g569uhfdbesujbgpzk77h.png)
f(x) is not defined where the term of the denominator is zero.
This happens when x = 4, x = -5 or x = -1
The x-intercepts is the points where f(x) = 0
this happens when x = -7 and x = 3
Notice that x = -1 can't be a x-intercept because the function is not defined at this point.