Question

Find degree measures of marked angles in fig 5.47​

Answer 1

50+P=125 exterior angle of the triangle is equal to the sum of two opposite interior angle

P=125-50=75°

q+125=180 linear pair

q=180-125=55°

r=q=55° vertically opposite angle

s+85=125 exterior angle of the triangle is equal to the sum of two opposite interior angle

s=125-85=40°

s+t=180 linear pair

t=180-40=140°

u=s=40° vertically opposite angle

w=65° vertically opposite angle

v+u+w=180 sum of interior angle of the triangle is 180

v+40+65=180

v=180-105=75°

x+65=180 linear pair

x=180-65=115°