The following function models the population of rabbits, in thousands, in a state x years after 1990.
![f(x)=110\cdot(1.004)^x](https://img.qammunity.org/2023/formulas/mathematics/college/ecescyvz82qhhspbds4bm705r70p0v6c8q.png)
What is the approximate population of rabbits in 2012?
Count the number of years after 1990 to 2012.
That's 22 years so we have x = 22
Let us substitute x = 22 into the above function
![\begin{gathered} f(22)=110\cdot(1.004)^(22) \\ f(22)=110\cdot(1.091796) \\ f(22)=120.09756 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3ozwd942zrrgby764pialw6e12ie5vkcz0.png)
That is approximately 120 thousands or 120,000