Question

Write the first five terms of the geometric sequence with a1 = 16 and common ratio r= 3/2

Answer 1

From the problem, we need to find the first five terms of the geometric sequence.

The first term, a1 = 16 and the common ratio, r = 3/2

Note that the succeeding term is the previous term multiplied by the common ratio.

This will be :

`\begin{gathered} a_2=a_1r=16((3)/(2))=24 \\ a_3=a_2r=24((3)/(2))=36_{} \\ a_4=a_3r=36((3)/(2))=54 \\ a_5=a_4r=54((3)/(2))=81 \end{gathered}`

The geometric series is :

an = {16, 24, 36, 54, 81, ...}

The answer is B. an = {16, 24, 36, 54, ...}