Question

Ronald was 1.5 times olderthan Megan. If Ronald was 27years old, how old is Megan?Write an equation to solve.

Answer 1

Let x represent Ronald's age, and y represent Megan's age.

Thus,

`\begin{gathered} x\Rightarrow Ronald^(\prime)s\text{ age} \\ y\Rightarrow Megan^(\prime)s\text{ age} \end{gathered}`

Given that Ronald was 1.5 times older than Megan, we have the equation to be represented

`x=1.5y\text{ ---- equation 1}`

If Ronald was 27 years old, we have

`x=27`

Substituting the value of 27 for x into equation 1, we have

`\begin{gathered} 27=1.5y \\ solve\text{ for y by dividing both sides by the coefficient of y,} \\ (27)/(1.5)=(1.5y)/(1.5) \\ \Rightarrow y=18 \end{gathered}`

This implies that Megan's age is

`18\text{ years}`