Question

It wants me to solve for the other leg and for the hypotenuse of the 45-45-90 triangle

Answer 1

Given:

In the given 45-45-90 triangle,

Use the tan ratio,

`\begin{gathered} \tan 45^(\circ)=\frac{opposite\text{ side}}{\text{adjacent side}} \\ \tan 45^(\circ)=(v)/(7) \\ 1=(v)/(7) \\ v=7 \end{gathered}`

Use the cosine ratio,

`\begin{gathered} \cos 45^(\circ)=\frac{adjacent\text{ side}}{\text{hypotenuse}} \\ \cos 45^(\circ)=(7)/(u) \\ \frac{1}{\sqrt[]{2}}=(7)/(u) \\ u=\frac{7}{\sqrt[]{2}} \\ u=7\sqrt[]{2} \end{gathered}`

Answer: option a)

`u=7\sqrt[]{2},v=7`