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What values of c and d make the equation true?3/162x2y3 –3x+y{VoyaO c = 2, d = 2O c = 2, d = 4O c = 6, d = 2O c= 6, d = 4

User DougJones
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1 Answer

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we have the expression


\sqrt[3]{162x^cy^5}=3x^2y(\sqrt[3]{6y^d)}

Verify for each option

1) For c=2 and d=2

substitute


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User Csaba Toth
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