Question

What values of c and d make the equation true?3/162x2y3 –3x+y{VoyaO c = 2, d = 2O c = 2, d = 4O c = 6, d = 2O c= 6, d = 4

Answer 1

we have the expression

`\sqrt[3]{162x^cy^5}=3x^2y(\sqrt[3]{6y^d)}`

Verify for each option

1) For c=2 and d=2

substitute