We have a line with equation:

The expression of the line is the slope-point form, that is:

where (x0,y0) is a point of the line and m is the slope.
As in this case, m = 9/7, then the slope is 9/7.
By inspecting the equation, the graph of the line has a slope of 9/7.
We also know that (x0,y0) = (-4, 5), that belong to the line.
By inspecting the equation the graph of the line passes through the point (-4, 5).
To find the value of y(3) we replace x with the value 3:

The value of y(3) is 14. The point is (3, 14).