Question

In ABCD, the measure of ZD=90°, CB = 53, BD = 45, and DC = 28. What ratiorepresents the sine of ZB?|

Answer 1

Step 1 :

In this question, we asked to find the value of

`\sin \text{ B}`
`\begin{gathered} \text{where }\angle D=90^0 \\ BD\text{ = 45} \\ DC\text{ = 28} \\ BC\text{ = 53} \end{gathered}`

Step 2 :

We can are see clearly that 28 , 45, 53 ) iPythagoras' Triple, since:

`28^2+45^2=53^2`

Step 3 :

`\begin{gathered} \sin \text{ B = }(28)/(53) \\ =\text{ 0.5283} \end{gathered}`

CONCLUSION :

`\sin \text{ B = 0.5283}`