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Solve the system algebraically 5 x - y = 0

User JWL
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1 Answer

4 votes

Answer:

To solve the system of equations,


\begin{gathered} 5x-y=0 \\ (y^2)/(90)-(x^2)/(36)=1 \end{gathered}

Solving 1st equation we get,


y=5x
(y^2)/(90)-(x^2)/(36)=1

Substitute y=5x in the above equation, we get


((5x)^2)/(90)-(x^2)/(36)=1
(25x^2)/(90)-(x^2)/(36)=1
(5x^2)/(18)-(x^2)/(36)=1
(10x^2-x^2)/(36)=1
(9x^2)/(36)=1
(x^2)/(4)=1
x^2=4
x=\pm2

when x=2, we get y=5x=5(2)=10

when x=-2, we get y=5x=5(-2)=-10

There are two solution for the given system.


(2,10),(2,-10)

Answer is: x=2,y=10 and x=2,y=-10

User Jashwant
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