Question

is a projectile is launched from a height of 5 m with an intial velocity of 25 meters per second, how many seconds will it take the projectile to hit the ground

Answer 1

In this problem we know that the initial velocity in the horizontal axis is 25, however the initial velocity in the y axis will be o so we can use this equation:

`y=y_0+v_it+(1)/(2)at^2`

So to find the time the object get the grownd we can replace the initial high for 5 miter, the final one for 0 and the aceleration by -9.8 (gravity) so:

`0=5+0(t)+(1)/(2)(-9.8)t^2`

and we solve for t so:

`\begin{gathered} 9.8t^2=5\cdot2 \\ t^2=(10)/(9.8) \\ t\approx\sqrt[]{1} \\ t\approx1 \end{gathered}`

So the projectil takes one secon to hit the grownd