Question

A person has a sample of gas with a volume of 9.02L and a temperature of 585.57k. If the volume of the container is reduced to 2.24L, what will the new temperature of the gas be in Kelvin?

Answer 1

Step 1 - Understanding the relation between volume and temperature for a gas sample

There are three main variables that can change the state of a gas sample: temperature, pressure and volume. If the pressure (P) is kept constant, the volume (V) becomes proportional to the temperature (T) in K:

`(V_1)/(T_1)=(V_2)/(T_2)`

Step 2 - Substituting the values in the equation above

We know, from the exercise, that V1 = 9.02 L and T1 = 585.57 K, and V2=2.24 L. Substituting these values in the equation above:

`\begin{gathered} (9.02)/(585.57)=(2.24)/(T_2) \\ \\ T_2=(2.24*585.57)/(9.02)= \end{gathered}`