Answer:
The molal concentration of the solution is approximately 0.124 molal
Step-by-step explanation:
The given parameters are;
The reduced freezing point of the water = -0.23°C
For freezing point depression of a solution, we have;
=
· b·i
Where;
= The freezing point depression
= Cyroscopic constant (The freezing-point depression constant) = 1.86° Cm⁻¹ for water
b = The molality of the solution
i = van't Hoff factor = 1
Therefore;
=
Where;
= The freezing point of pure water = 0°C
= The freezing point of the solution = -0.23°C
∴
=
= 0°C - (-0.23°C) = 0.23 °C
From,
=
· b·i, we have;
0.23°C = 1.86°C/m × b × 1
∴ b = (0.23°C/1.86°C/m) ≈ 0.124 molal
Therefore, the molal concentration of the solution, b ≈ 0.124 molal.