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A vector has an x-componentof -309 m and a y-componentof 187 m.Find the magnitude and direction of thevector.

User Damoiser
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1 Answer

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In order to find the magnitude we will follow the next formula


M=\sqrt[]{C^2_x+C^2_y}

Cx= -309

Cy=187

We substitute the values


M=\sqrt[]{(-309)^2+(187)^2}=361.18m

Then for the direction we need o use the next formula


\theta=\tan ^(-1)((Cy)/(Cx))

We substitute the variables


\theta=\tan ^(-1)((187)/(-309))=-31.181

In order to obtain the direction we need to add to the angle 180°

the direction is -31.181+180=148.82°

ANSWER

magnitud =361.18

direction =148.82°

User Stig Perez
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5.5k points