Given data:
* The weight of the crate is 65 kg.
* The acceleration of crate and helicopter is,

Solution:
(1). The forces acting on the crate is represented as,
The y-component of tension is balancing the weight of the crate.
Thus, the y-component (vertical) of tension is,

Where m is the mass of crate and g is the acceleration due to gravity,
Substituting the known values,

Thus, the vertical component of the tesnion is 637 N.
(2). The x-component of tension in the cable is,

Thus, the tension in the cable is,
![\begin{gathered} T=\sqrt[]{T^2_x+T^2_y} \\ T=\sqrt[]{195^2^{}+637^2} \\ T=666.2\text{ N} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/1cx2i3oqg57wo78cpr5p9gc8c22nm0ktlh.png)
Hence, the tesnion in the cable is 666.2 N.
(3). The angle of tension with the horizontal is,

Thus, the angle made by the tension with the horizontal is 73.14 degree.