Question

The proportion of passengers who miss a flight for which they have a reservation is0.0995. Suppose a flight 290 reservations. Find the standard deviation of the sampleproportion, ºf, rounded to the nearest ten-thousandth (4 decimal places).

Answer 1

Standard deviation of the sample proportion = 0.0176

Step-by-step explanation

For a distribution with proportion, p, the standard deviation of the sample proportion is given as

`\sigma_x=\sqrt[]{(p(1-p))/(n)}`

where

p = sample proportion = 0.0995

n = sample size = 290

`\begin{gathered} \sigma_x=\sqrt[]{(p(1-p))/(n)} \\ \sigma_x=\sqrt[]{(0.0995(1-0.0995))/(290)} \\ \sigma_x=\sqrt[]{(0.0995(0.9005))/(290)} \\ \sigma_x=\sqrt[]{(0.08959975)/(290)} \\ \sigma_x=\sqrt[]{0.0003089647} \\ \sigma_x=0.0176 \end{gathered}`

Hope this Helps!!!