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A father is 28 years older than his daughter. In six years' time, he will be three times her age. Find their present ages.

Please include your working out!!

User Chris Van De Steeg
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2 Answers

9 votes
9 votes

A father is 28 years older than his daughter. In six years' time, he will be three times her age. Find their present ages.


Please include your working out!!
User Torvin
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27 votes
27 votes

Answer:

Daughter's age = 6

Father's age = 34

Explanation:

Let the age of daughter be x

Then the age of father will be x + 28

In 6 years time:-

The age of father = x + 28 + 2 = 30 + x

The age of daughter = x + 6

According to the question,

Father will be three times the age of his daughter.

30 + x = 3(x + 6)

30 + x = 3x + 18

x - 3x = 18 - 30

-2x = - 12

x = - 12/-2

x = 6

So therfore,

Daughter's present age = 6 years

Father's present age = 34 years

Hope this helps :)

User Rantoniuk
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