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hello I was trying to do this question on my own for a while and haven't gotten the answer I need but hopefully you can help me and thank you for your time

hello I was trying to do this question on my own for a while and haven't gotten the-example-1
User Ytropek
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given diameter (D) of wheel = 24 in rotation of wheel 455 rpm

circunference (C) = π⋅D


\begin{gathered} C=\pi*24\text{ in } \\ C=\pi*(24)/(12)=\pi2\text{ ft/r} \end{gathered}

455 rpm x 60 = 27300 r/h

27300 x 2π = 54600π ft/h

5280 ft = 1 mile


(54600\pi)/(5280)=10.34\pi

or 10.34 π mph

User Ian Ash
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