335,014 views
41 votes
41 votes
A bag contains 42 red, 45 green, 20

yellow, and 32 purple candies. You
pick one candy at random. Find the
probability that it is green or yellow.

User Nightgaunt
by
3.0k points

2 Answers

14 votes
14 votes

Answer:

Explanation:

Total sample space , n (s) = 139

no of green candies , n (g) = 45

no. of yellow candies , n (y) = 20

Probability that is green or yellow is

P( g or y) = P(g) + P(y)

= n(g) / n(s) + n (y) / n(s)

= 45 / 139 + 20 / 139

= 65 / 139

hope it will help :)

User Etlsh
by
2.2k points
14 votes
14 votes

Answer:

65/139 fraction form

0.47 decimal form

User Mark Schill
by
3.0k points
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