Question

Two identical R = 6.77 ohm light bulbs are is series circuit

with a 17.8 volt battery. What is the power (watt) of both
glowing bulbs?

Answer 1

the power of the two light bulbs is 23.4 W

Step-by-step explanation:

Given;

the resistance of the two identical light bulbs in series, R₁ and R₂ = 6.77 ohms and 6.77 ohms respectively

battery voltage , V = 17.8 V

The equivalent resistance of the two light bulbs, R = R₁ + R₂

R = 6.77 + 6.77

R = 13.54 ohms

The power of the two light bulbs is calculated as follows;

`P = IV = ((V)/(R) )V = (V^2)/(R) = (17.8^2)/(13.54) = 23.4 \ W`

Therefore, the power of the two light bulbs is 23.4 W