Question

I need the answer i can’t figure it out and my teacher won’t help

Answer 1

From the given question, we have

To solve for the ramp angle from the ground, we use trigonometric ratios.

Thus, we have

`\sin\theta=(opposite)/(hypotenuse)`

This gives

`\begin{gathered} \sin\theta=(11.5)/(175) \\ \Rightarrow\sin\theta=0.06571 \\ take\text{ the sine inverse of both sides} \\ \sin^(-1)(\sin\theta)=\sin^(-1)(0.06571) \\ \theta=3.77^(\circ\:) \\ \therefore \\ \theta\approx3.8\degree(nearest\text{ tenth\rparen} \end{gathered}`

Hence, to the nearest tenth, the ramp angle is

`3.8\degree`