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( 3y + 1 )( 3y - 1 )Determine each product

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It is important to know that a Product is the result of a multiplication.

You have the following expression given in the exercise:


\mleft(3y+1\mright)\mleft(3y-1\mright)​

Notice that it is the multiplication of two Binomials and it has this form:


(a+b)(a-b)

By definition:


(a+b)(a-b)=a^2-b^2

This is called "Difference of two squares".

You can identify that, in this case:


\begin{gathered} a=3y \\ b=1 \end{gathered}

Therefore, you get:


\mleft(3y+1\mright)\mleft(3y-1\mright)​=(3y)^2-(1)^2=9y^2-1

The answer is:


9y^2-1

User Akelec
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