Question

A force F1 of magnitude 4.80 units acts on an object at the origin in a direction = 27.0° above the positive x-axis. (See the figure below.) A second force F2 of magnitude 5.00 units acts on the object in the direction of the positive y-axis. Find graphically the magnitude and direction of the resultant force F1 + F2.magnitude unitsdirection ° counterclockwise from the +x-axis

Answer 1

We will determine the magnitude of the final component as follows:

`\begin{gathered} m=√((5cos(27))^2+(5sin(27)+4.8)^2)\Rightarrow m=8.356527029... \\ \\ \Rightarrow m\approx8.36 \end{gathered}`

So, the magnitude is approximately 8.36.

And the direction will be approximately 57.8° counter-clockwise.

This can be seeing as follows: