Question

Part AWhat is the mass in grams of 17.96 mL of acetone?Express your answer to four significant figures and include the appropriate units.mass = Value and UnitsPart BWhat is the volume in milliliters of 7.40 g of acetone?Express your answer to three significant figures and include the appropriate units.V = Value and Units

Answer 1

Part A:

Ans: Mass=14.11 g.

Given:

The volume of acetone, V=17.96 mL.

We know, the density of acetone, D=0.7857 g/mL.

The mass in grams of acetone is,

`\begin{gathered} M=VD \\ =17.96\text{ mL}*0.7857\text{ g/mL} \\ =14.11\text{ g} \end{gathered}`

Therefore, mass of acetone in grasm rounded upto four significant figures is 14.11 g.

Mass=14.11 g.

Part B:

Ans: V=9.42 mL

Given

The mass of acetone, M=7.4 g.

We know, the density of acetone, D=0.7857 g/mL.

The volume in mL of acetone is,

`\begin{gathered} V=(M)/(D) \\ =\frac{7.40\text{ g}}{0.7857\text{ g/mL}} \\ =9.42\text{ mL} \end{gathered}`

Therefore, voulme of acetone in mL rounded upto three significant figures is 9.42 mL.

Volume, V=9.42 mL