201k views
3 votes
How much heat is released when a 50 g piece of paraffin cools from 55⁰C to 18⁰. Specific heat of paraffin = 2.9J/gC

User Tzane
by
7.5k points

1 Answer

4 votes

Answer:

Q = -5,365 J

Step-by-step explanation:

To find the amount of heat released, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = heat (J)

-----> m = mass (g)

-----> c = specific heat capacity (J/g°C)

-----> ΔT = T₂ - T₁ = change in temperature (°C)

"T₂" represents the final temperature and "T₁" represents the initial temperature. You can plug the given values into the equation and solve to find "Q".

Q = ? J c = 2.9 J/g°C

m = 50 g ΔT = 18°C - 55°C = -37°C

Q = mcΔT <----- Given equation

Q = (50 g)(2.9 J/g°C)(-37°C) <----- Insert values

Q = -5,365 J <----- Multiply

*the answer is negative because the reaction is exothermic (heat is being released from the system)

User Parvesh Khan
by
9.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.