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Solve the system using the addition method 5x-2y=32x-y=0What is the y-valueA. 3B. 6C. -3D. none of the above

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First, we multiply the first equation by "2":


\begin{gathered} 2*\lbrack5x-2y=3\rbrack \\ 10x-4y=6 \end{gathered}

Then, we multiply the second equation by "-5":


\begin{gathered} -5*\lbrack2x-y=0\rbrack \\ -10x+5y=0 \end{gathered}

The two new equations are:


\begin{gathered} 10x-4y=6 \\ -10x+5y=0 \end{gathered}

We add both equations and solve for y. The steps are shown below:


\begin{gathered} 10x-4y=6 \\ -10x+5y=0 \\ ----------- \\ y=6 \end{gathered}

The correct answer is y = 6.

AnswerB
User Fatah
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