Question

What is the equation of the circle whose diameter has endpoints (10,1) and (-8,1)

Answer 1

Since the endpoints of the diameter are (10, 1) and (-8, 1)

Then the center of the circle is the midpoint of these 2 points

We will use the rule of the midpoint to find the center

`M=((x_1+x_2)/(2),(y_1+y_2)/(2))`

`\begin{gathered} M=((10+-8)/(2),(1+1)/(2)) \\ \\ M=((2)/(2),(2)/(2)) \\ \\ M=(1,1) \end{gathered}`

The center of the circle is (1, 1)

The length of the diameter is the difference between the x-coordinate