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Х о 1 2 3 4 у -5 4 13 22 31

Х о 1 2 3 4 у -5 4 13 22 31-example-1

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We can take any 2 points both from x and y and use the equation of a line formula to find out the equation of the line represented by the points in the table.

Let's take the points:


\begin{gathered} (x_1,y_1)=(0,-5) \\ (x_2,y_2)=(1,4) \end{gathered}

The equation of a line formula is:


y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)

Let us plug in the points into this formula and do a little algebra to re-arrange the equation in the slope-intercept form, which is y = mx + b. The steps are shown below:


\begin{gathered} y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1) \\ y-(-5)=(4-(-5))/(1-0)(x-0) \\ y+5=(4+5)/(1)(x) \\ y+5=(9)/(1)(x) \\ y+5=9x \\ y=9x-5 \end{gathered}

The slope-intercept form is given by:


y=9x-5

Where 9 is the slope and -5 is the y-intercept (y-axis cutting point)

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