Step-by-step explanation:
Given;
We are given a symmetrical pool as indicated in the attached picture.
The pool consists of two sectors and two triangles and each pair has the same dimensions.
The dimensions are as follows;


Required;
We are required to calculate the area of the pool.
Step-by-step solution;
We shall begin by calculating the area of the sector and the formula for the area of a sector is;

Where the variables are;

We now substitute and we have the following;



Since there are two sectors of the same dimensions, the area of both sectors therefore would be;


Next we shall calculate the area of the triangles.
Note the formula for calculating the area of a triangle;

Note the variables are;

The area therefore is;



For two triangles the area would now be;


Therefore, the area of the pool would be;


Rounded to the tens place, we would now have,
ANSWER:

Option D is the correct answer