Question

Unpolarized light with intensity 455.16 W/m2 passes first through a polarizing filter with its axis vertical, then through a polarizing filter with its axis 33.33o from vertical. What light intensity emerges from the second filter ?

Answer 1

Given:

The intensity of unpolarized incident light is

`I_0=455.16\text{ W/m}^2`

It passes first through a polarizing filter with its axis vertical

The second polarising filter is at an angle of,

`\theta=33.33\degree`

from the vertical

To find:

What light intensity emerges from the second filter ?

Step-by-step explanation:

According to the Malus law, the emergent light intensity is,

`\begin{gathered} I=I_0cos^2\theta \\ =455.16* cos^233.33\degree \\ =317.74\text{ W/m}^2 \end{gathered}`

Hence, the required intensity is

`317.74\text{ W/m}^2`