Question

How many moles of O2 is in a 5.6 L sample of O2 measured at 250 kPa and 18°C?

Answer 1

578.66 mol

Step-by-step explanation

Given:

Volume, V = 5.6 L

Temperature, T = 18° C = 18 + 273 = 291 K

Pressure, P = 250 kPa = 250000 Pa

Using the ideal gas equation, we can solve for the number of moles:

`PV=\text{nRT}`

Put the given values into the ideal gas equation to get the number of moles:

`\begin{gathered} 250000*5.6=n*8.314*291 \\ 1400000=2419.374n \\ \text{Divide both sides by 2419.374} \\ (1400000)/(2419.374)=(2419.37n)/(2419.374) \\ n=578.66\text{ mol} \end{gathered}`