Question

Hello, is it possible to help me understand this question a little better?

Answer 1

`\begin{equation*} x^2-2x+3-(8)/(3x+2) \end{equation*}`

1) Since the degree of the denominator is lower than the numerator's we can divide these expressions through long division that way:

As we can see in each step the aim is to cancel the leading coefficient.

2) Note that a Long Division, has a way to write its answer so we can tell that this is the answer:

`(3x^3-4x^2+5x-2)/(3x+2)=\quad x^2-2x+3-(8)/(3x+2)`

Note that the remainder is written above the divisor on the final answer.