Question

Find a recursive formula for the following sequence:4, 11, 25, 53, 109, ...

Answer 1

Notice the following pattern in the given sequence:

`\begin{gathered} 11=4\cdot2\text{ +3,} \\ 25=11\cdot2+3, \\ 53=25\cdot2+3, \\ 109=53\cdot2+3. \end{gathered}`

Therefore, the n-term of the sequence has the following form:

`a_n=a_{n-1\text{ }}+3.`

Answer:

`a_n=a_{n-1\text{ }}+3.`